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1. Use the Law of Levers to solve the problem, x1y1=x2y2.

A 27 kg weight is placed 10 feet from the fulcrum on one side, and a 30 kg weight is placed x feet from the fulcrum on the other side. what is x?
A. 9
B. 15
C. 12
D. 8
2. Which equation is the inverse variation relationship for the following quantities? y =-12 when x = 5
A. y = -2.4x
B. y/x = -2.4
C. xy = -60

1 Answer

3 votes
1) Never heard of someone referring to the Law of Levers before, must be showing my age. A system as you describe is at equilibrium when the net torque is equal to zero. Since torque is Fr=mgr so for this system we have a sum of:

27g*10+30g*x=0 The sum must be zero to be at equilibrium, dividing both sides by g you have:

270+30x=0

270=-30x

x=-9

The negative just indicates that the magnitude of 9 is on the opposite side of the fulcrum, so x=9ft in magnitude.

2) Inverse variation is of the form y=k/x, in this case we are given a point so we can solve for the constant, k, of variation...

y=k/x, and we are given y=-12 when x=5 so

-12=k/5

k=-60 so the equation is:

y=-60/x which can be expressed as

xy=-60


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