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How many moles of carbon dioxide gas can be produced when 12.8 moles of benzene (C6H6) react with excess oxygen? Unbalanced equation: C6H6 + O2 → CO2 + H2O Show, or explain, all of your work along with the final answer.

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1) 2C₆H₆ + 15O₂ = 6H₂O + 12CO₂

2) n(C₆H₆)/2=n(CO₂)/12

n(CO₂)=6n(C₆H₆)

n(CO₂)=6*12.8 mol = 76.8 mol
User Marc Cohen
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