165k views
4 votes
Rachel has an unknown sample of a radioisotope listed in the table. Using a special technique, she is able to measure the mass of just the unknown isotope as 104.8 kg at 12:02:00 P.M. At 4:11:00 P.M. on the same day, the mass of the unknown radioisotope is 13.1 kg. Which radioisotope is in the sample?

User StackHola
by
7.6k points

2 Answers

2 votes
Barium-139 is the correct answer.
User Steve Wilhelm
by
8.4k points
5 votes

Answer:

Barium-139

Step-by-step explanation:

initial mass of the sample at 12:02:00 PM is given as


m_1 = 104.8 kg

Mass of the sample at 4:11:00 PM is given as


m_2 = 13.1 kg

so here since it is a sample of radioactive isotope so here we will say


m_2 = m_1 e^(-\lambda t)

now from above data we know that the time taken to reduce the mass is


t = 4 hours 9 minutes


t = 4.15 hours

now from above equation we will have


13.1 = 104.8 e^(-\lambda(4.15))


\lambda(4.15) = 2.08


\lambda = 0.50 per hour

so here half life is given as


T_(1/2) = (ln2)/(\lambda)


T_(1/2) = 1.4 hours

So here this isotope must be the one which will have half life of 1.4 hours

So it is nearly Barium-139

User Buz
by
8.4k points