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1 vote
The equation of line MN is y=3/4x+5 In slope-intercept form, write the equation of the line that is perpendicular to MN and that passes through the point (–6, –2).

User Gasho
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6.3k points

2 Answers

7 votes
For a line to be perpendicular to a reference line, it must have a slope that is the negative reciprocal of the reference line's slope, mathematically:

m1*m2=-1, where m1 and m2 are the slopes of the perpendicular lines for them to be perpendicular. In this case, the slope of the reference line is 3/4 so:

3m/4=-1

3m=-4

m=-4/3

So the perpendicular line will have a slope of -4/3, then the line is currently:

y=-4x/3+b, we can solve for b using the point that we must pass through.

-2=-4(-6)/3+b

-2=8+b

-10=b, so our perpendicular line is:

y=-4x/3-10 or more neatly in my opinion:

y=(-4x-30)/3
User Mdrg
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7.4k points
6 votes

Answer:

y = -4/3x - 10

Explanation:

i got it right on EDG2020

User Omkar Neogi
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6.2k points
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