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F(x)=3x+1 and g(x)=x^2-6, find (f+g)(x)

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Answer: x^2+3x-5

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Work Shown:

(f+g)(x) = f(x) + g(x)
(f+g)(x) = [ f(x) ] + [ g(x) ]
(f+g)(x) = [ 3x+1 ] + [ x^2-6 ]
(f+g)(x) = 3x+1 + x^2-6
(f+g)(x) = x^2 + 3x + (1 - 6)
(f+g)(x) = x^2 + 3x - 5
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