The concentration of nitrate ion in a solution that contains 0.600 m aluminum nitrate is

asked Jan 2, 2018 176k views

3 votes

6.8k points

Please log in or register to add a comment.

1 vote

Al(NO₃)₃(aq) → Al³⁺(aq) + 3NO₃⁻(aq)

c(NO₃⁻)=3c(Al(NO₃)₃)

c(NO₃⁻)=3*0.600 mol/L=1.800 mol/l

TcKs answered Jan 7, 2018

by TcKs

7.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.7m questions

11.3m answers