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A 300-kg bear grasping a vertical tree slides down at constant velocity. the friction force between the tree and the bear is

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The friction force between the tree and the bear is 3000 N. The acceleration is 0 since the bear slides down at a constant velocity. The sum of the forces is 0. Thus;

Upward friction + downward weight = 0

F-mg = 0

F = mg

F = (300 kg) (10 m/s² the acceleration due to gravity)

F = 3000 N frictional force

User Sacohe
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