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What mass of helium, in grams, is required to fill a 6.1-l balloon to a pressure of 1.1 atm at 25 °c?
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What mass of helium, in grams, is required to fill a 6.1-l balloon to a pressure of 1.1 atm at 25 °c?

User Jashim
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1 Answer

1 vote
PV=nRT
(1.1)(6.1)=(n)(0.08201)(298)
6.71=n(0.08201*298)
n=0.2745613769 moles Helium
n(Mm)=mass
0.2745613769(4.00)
1.098245508 grams of Helium
User Zerweck
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7.6k points
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