Question

(tco 5) how many 4-bit parallel adders are required to add the numbers 5,345 and 3,892? explain how you got your answer.

Answer 1

The sum is 9237. To express this as binary requires log(9237)/log(2) bits ≈ 13.2 bits, rounded up at least 14 bits. (You can check: 2^13 is not enough, 2^14 is enough)

So you need four 4-bit adders, giving you 16 bits resolution.