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A leaky faucet drips once each second. at this rate, it takes 1 hour to fill a 1-liter graduated cylinder to the 200-cm3 mark. what unit conversion do you need in order to calculate the average volume of a single drop in cm3?

User Fbl
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Define
v = volume of a drop per second, cm³/s

The time taken to fill 200 cm³ is 1 hour.
Let V = 200 cm³, the filled volume.
Let t = 1 h = 3600 s, the time required to fill the volume.

Therefore,

(200 \, cm^(3))/(v \, cm^(3)/s) = 3600 \, s \\ v = (200)/(3600) =0.0556 \, cm^(3)

The average volume of a single drop is approximately 0.0556 cm³.

Answer: 0.0556 cm³

User Zorji
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