Question

A doctor’s office has a jar of 22 lollipops; 12 are lime, 7 are cherry, 2 are grape, and 1 is orange. If Jennifer and Seth each take and eat a lollipop at random, what is the probability that Jennifer will choose a grape lollipop and Seth will choose a cherry one?

Answer 1

The probability that Jennifer will choose a grape lollipop and Seth will choose a cherry one is 7/242.

Step-by-step explanation:

To find the probability that Jennifer will choose a grape lollipop and Seth will choose a cherry one, we need to calculate the individual probabilities of each event and then multiply them together. First, let's find the probability of Jennifer choosing a grape lollipop. There are a total of 22 lollipops in the jar, and 2 of them are grape, so the probability of Jennifer choosing a grape lollipop is 2/22 or 1/11. Next, let's find the probability of Seth choosing a cherry lollipop. There are 7 cherry lollipops out of the 22, so the probability of Seth choosing a cherry lollipop is 7/22. To find the probability of both events occurring, we multiply the probabilities together: (1/11) * (7/22) = 7/242.

Answer 2

the equation we need to do is 1/11 times 7/22 so the answere would be
7/242