Question

Arrange the examples in order, starting with the object that has the least amount of energy. In each case, assume there’s no friction. Use g = 9.8 m/s2, PE = m × g × h, and .

Tiles
a book with a mass
of 0.75 kilograms
resting on a shelf at a
height of 1.5 metersa brick with a mass of
2.5 kilograms falling
with a velocity of
10 meters/second
when it’s 4 meters
above grounda ball with a mass of
0.25 kilograms rolling
on flat ground with a
velocity of
10 meters/seconda stone with a mass
of 0.7 kilograms being
held still at a height of
7 meters

Answer 1

Answer: a book with a mass of 0.75 kilograms resting on a shelf at a height of 1.5 meters< a ball with a mass of 0.25 kilograms rolling on flat ground with a velocity of 10 meters/second< a stone with a mass of 0.7 kilograms being held still at a height of 7 meters< a mass of 2.5 kilograms falling with a velocity of 10 meters/second when it’s 4 meters above ground

Explanation: Gravitational potential energy is the energy possessed by an object due to its position or height.Kinetic energy is the energy possessed by an object by virtue of its motion.

`P.E=m* g* h`

m= mass of object

g= gravity

h= height of an object

`K.E=(1)/(2)* mv^2`

v= velocity of object

`(1kgm^2s^(-2)=1Joule)`

A) a book with a mass of 0.75 kilograms resting on a shelf at a height of 1.5 meters

`P.E=0.75kg* 9.8ms^(-2)* 1.5m=11.025J`

B) a mass of 2.5 kilograms falling with a velocity of 10 meters/second when it’s 4 meters above ground

`K.E=(1)/(2)* mv^2`

`K.E=(1)/(2)* 2.5kg* (10)^2=125J`

`P.E=m* g* h`

`P.E=2.5* 9.8* 4=98J`

total energy= (K.E+P.E) =(125+98) =223J

C) a ball with a mass of 0.25 kilograms rolling on flat ground with a velocity of 10 meters/second

`K.E=(1)/(2)* mv^2`

`K.E=(1)/(2)* 0.25* (10m/s)^2=12.5J`

D) a stone with a mass of 0.7 kilograms being held still at a height of 7 meters

`P.E=0.7kg* 9.8ms^(-2)* 7m=48.02J`

Answer 2

the answer is the 1-1, 2-4,3-2,4-3... hope it helps and yall understand these.. :)