Question

Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner: CS2 + 3O2 → CO2 + 2SO2 What is the volume of sulfur dioxide (SO2 gas), formed when 2 moles of carbon disulfide (CS2) are burned? The reaction is taking place at STP.

Answer 1

CS₂ + 3O₂ = CO₂ + 2SO₂

n(CS₂)=2 mol
V₀=22.4 L/mol

V(SO₂)/2V₀=n(CS₂)

V(SO₂)=2V₀n(CS₂)

V(SO₂)=2*22.4*2=89.6 L

Answer 2

Answer: 98.6 Litres

Explanation: From the given chemical equation :

CS2 + 3O2 → CO2 + 2SO2

From the equation above,

1 mole of CS2 gas produces 2 moles of SO2 gas

Therefore,

2 moles of CS2 gas will produce (2*2) moles of SO2 gas

= 4 moles of SO2 gas

Also at STP,

The volume of 1 mole of gas is 22.4 Litres

Hence,

The volume of 4 moles of SO2 gas produce will be

22.4*4 Litres

= 98.6 Litres

Hence, the volume of SO2 gas produce from 2 moles of CS2 in the given reaction at STP is 98.6 Litres.