Step 1
The reaction provided:
Li3N + 3H20 => NH3 + 3LiOH (completed and balanced)
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Step 2
Information provided:
6.75 moles of lithium nitride (Li3N)
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Information needed:
The molar mass of Lithium hydroxide (LiOH) = 23.9 approx.
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Step 3
By stoichiometry,
Procedure:
Li3N + 3H20 => NH3 + 3LiOH
1 mole Li3N --------------- 3 x 23.9 g LiOH
6.75 moles Li3N --------------- X
X = 6.75 moles Li3N x 3 x 23.9 g LiOH/1 mole Li3N
X = 484 g LiOH
Answer: 484 g of LiOH