Question

Using the quadratic equation to solve 3x^2+11x-4=0, the value of b^2-4ac is

-26
73
169

Answer 1

Use standered form to determine the values of a,b,and c.
Standered form:

`ax^2+bx+c=0`We are given:

`3x^2+11x-4`

a=3
b=11
c=-4

Plug the given values in the discriminant:

`b^2-4ac`

`(11)^2-4(3)(-4)`

`121-(4)(3)(-4)`

`121-(12)(-4)`

`121-(-48)`

`121+48`

Final answer:169