Question

The molar mass of sucrose (C12H22O11) is 342.3 g/mol. A chemist has a 0.500-mol sample of sucrose. What is the mass, in grams, of this sample? 171 342 500 684

Answer 1

Answer: The mass of the sucrose is 171 g

Solution:

`\text{Number moles}=\frac{\text{Mass of the compound}}{\text{Molecular mass of the compound}}`

The molar mass of sucrose (
`C_(12)H_(22)O_(11)`) is 342.3 g/mol

Moles of sucrose = 0.500 moles

Mass of the sucrose :

`\text{Number moles of sucrose}=\frac{\text{Mass of the sucrose}}{\text{Molecular mass of the sucrose}}=`

`\text{Mass of the sucrose}=\text{Number moles of sucrose}* \text{Molecular mass of the sucrose}=0.500mol* 342.3g/mol=171.15\approx 171 g`

Hence, the mass of the sucrose is 171 g.

Answer 2

The mass of a chemical compound can be calculated for if its molecular mass and its moles is known. The product of the moles and the molecular mass will the give the mass in gram of that substance.
The appropriate formula for this work is : Mass of sucrose in 0.5mol = Moles * molecular weight
0.5 * 342.3 = 171.15
Thus, the mass in grams of the sample is 171.