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(6x−2)(x2+7x−8) in standard form
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(6x−2)(x2+7x−8) in standard form

User PaulEdison
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1 Answer

5 votes

Answer:


6x^3+40x^2-62x+16

Explanation:


6xx^2+6x\cdot \:7x+6x\left(-8\right)-2x^2-2\cdot \:7x-2\left(-8\right)\\=6x^3+42x^2-48x-2x^2-14x-16\\6x^3+40x^2-62x+16

User TheIcemanCometh
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