Question

What is the molarity of a solution of Cu2SO4 if 250.0 mL of solution contains 14.1 g of Cu2SO4?

Answer 1

Copper(I) compounds in aqueous solutions are unstable and disproportionate:
Cu₂SO₄ = Cu + CuSO₄
Necessary for dissolution of non-aqueous solvent.

M(Cu₂SO₄)=223.16 g/mol
m(Cu₂SO₄)=14.1 g
v=0.250 L

n(Cu₂SO₄)=m(Cu₂SO₄)/M(Cu₂SO₄)

c=n(Cu₂SO₄)/v=m(Cu₂SO₄)/(vM(Cu₂SO₄))

c=14.1/(0.250*223.16)=0.253 mol/L

0.253 M

Answer 2

A is 14.1 g

B is 0.0632 mol

C is 250.0 mL

D is 0.253 M

Step-by-step explanation:

I divided 14.1 g (A) by 223.2 and got 0.0632 mol (B).

For the second part, I divided 0.0632 by 250.0 mL (C) since 1000 is mL.

Then I used the equation and got 0.253 M (D)