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Cos θ = -3/5; θ is in QIII. What is sin θ?

4/5

-5/3

-4/5

5/3

User Sovalina
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1 Answer

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hello :
Cos θ = -3/5
sinθ = - 4/5
because : Cos² θ +sin²θ = (-3/5)²+(-4/5)2 =9/25+16/25 = 25/25 = 1
and θ is in QIII.where : sinθ < 0
User Renesis
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