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A box of mass 14 kg sits on an inclined surface with an angle of 52degrees. What is the component of the weight of the box along the surface?

User Sphennings
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2 Answers

6 votes

Answer:

108 N rounded

Step-by-step explanation:

User Suresh Chikkam
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First, we calculate for the weight of the object by multiplying the given mass by the acceleration due to gravity which is equal to 9.8 m/s²
Weight = (14 kg)(9.8 m/s²)
Weight = 137.2 N
The component of the weight that is along the surface of the inclined plane is equal to this weight times the sine of the given angle.
Weight = (137.2 N)(sin 52°)
weight = 108.1 N
User AntonAL
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