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A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to its position?

User Bicycle
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2 Answers

1 vote

Answer: B on edge 2023 =137

Step-by-step explanation:

User Anschauung
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8.2k points
5 votes

Answer: 137.2 J

Step-by-step explanation:

The gravitational potential energy of the bowling ball is given by:


U=mgh

where

m = 7.00 kg is the mass of the ball

g = 9.80 m/s^2 is the acceleration due to gravity

h = 2.00 m is the height above the ground

Substituting, we find


U=(7.00 kg)(9.8 m/s^2)(2.00 m)=137.2 J

User Z Boson
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8.3k points