Question

The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), benzoic acid (C6H5COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity.

Please list from Most Conductivity to Lease Conductivity in order (the ones I am typing out are in a random order):

calcium bromide
sugar
potassium bromide
benzoic acid

Answer 1

Ca2Br
KBr
C6H5COOH (benzonic acid)
C6H12O6 (sugar)

Answer 2

Answer : The order of conductivity from most conductive to least is this -

Calcium bromide
`(CaBr_(2))`, Potsassium bromide (KBr), Benzoic acid
`C_(6)H_(5)COOH` and last is sugar.

Explanation :

When dissolved in water
`(CaBr_(2))` produces three ions namely;
`Ca^(+2)` and
`2Br^(-)` which acts as best conductor amongst the given choices.

Next is potassium bromide when dissolved in water generates only two ions which are
`K^(+)` and
`Br^(-)` and acts as an conductor.

Benzoic acid
`C_(6)H_(5)COOH`, is a weak acid and is slightly ionized so it acts as an weak conductor.

Sugar is a non ionized compound so it is anon conductor.