The equation of a circle is:
(x-h)^2+(y-k)^2=r^2
Where (h,k) is the center of the circle and r is the radius of the circle. In this case we have (6,1) for the center and a radius of 5 so:
(x-6)^2+(y-1)^2=25
So any point that satisfies that equation lies on the circle.