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When solutions of barium chloride and lithium sulfate are mixed, the spectator ions in the resulting reaction are?

User Vladzaba
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Barium chloride and lithium sulfate are mixed, barium sulfate and lithium chloride are formed. Barium sulfate is obtained as a white precipitate and lithium chloride as an aqueous solution.

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User Jwm
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Answer : The resulting reaction will be,


Ba^(2+)(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,


BaCl_2(aq)+Li_2SO_4(aq)\rightarrow BaSO_4(s)+2LiCl(aq)

The ionic equation in separated aqueous solution will be,


Ba^(2+)(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)+2Li^+(aq)+2Cl^-(aq)

In this equation,
Li^+\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,


Ba^(2+)(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)

User HaydnD
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