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The equation for the circle is: x2+y2+14x+10y−7=0 . What is the center of the circle?
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5 votes
The equation for the circle is:

x2+y2+14x+10y−7=0 .



What is the center of the circle?

User Juninho Cruz
by
8.8k points

1 Answer

1 vote
use completion of sq method
x^2+y^2+14x+10y-7=0
(x+7)^2+(y+5)^2=7+49+25
(x+7)^2+(y+5)^2=81
so centre is(-7,-5) radius is9
User Ahmed Akhtar
by
8.3k points
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