66.9k views
5 votes
A small fair charges an admission fee for children and adults. The cost for admission is $3 per adult and $2 per child. On a certain day, total sales were $900, and 350 people attended the fair. How many children attended the fair that day?

2 Answers

7 votes
2c+3d=900
C=x
D=350-x
2x+3 (350-x)=900
Solve for x to get number of children
attended the fair that day
2x+1050-3x=900
2x-3x=900-1050
-1 x=-150
x=150 children

350-150=200 adult
User Vomi
by
9.0k points
6 votes

Answer:

150

Explanation:

I will call the number of adults that attended x, and the number of children that attended y.

if the total sales were $900, and the admission fee for adults is $3 and for children is $2:


3x+2y=900

i will call this equation 1.

then if 350 people attended:


x+y=350

i will call this equation 2.

multiplying equation 2 by -3


-3(x+y=350 )=-3x-3y=-1050

and adding this result to equation 1:


3x+2y=900 +


-3x-3y=-1050

------------------------


0x-y=-150\\y=150

where
y is the amount of childen that attended the fair.

User Afflatus
by
7.5k points