Question

The oxidation numbers of nitrogen in NH4+, N2O5, and NaNO3 are, respectively:

+3, +3, +5

-3, +5, +5

+3, +5, -4

-3, +3, +4

Answer 1

-III I
NH₄⁺

V -II
N₂O₅

I V -II
NaNO₃
-----------------------

-3 +5 +5

Answer 2

Answer: Option (b) is the correct answer.

Step-by-step explanation:

It is known that general charge on a hydrogen atom is +1, oxygen atom is -2, and sodium atom is +1.

Hence, oxidation number of nitrogen atom in the given species or compounds is as follows.

• 
  `NH^(+)_(4)`

x + 4(1) = 1

x = 1 - 4

= -3

• 
  `N_(2)O_(5)`

2x + 5(-2) = 0 (since total charge on the molecule is zero)

x = +5

• 
  `NaNO_(3)`

1 + x + 3(-2) = 0

x = +5

Thus, we can conclude that the oxidation numbers of nitrogen in NH4+, N2O5, and NaNO3 are -3, +5, +5 respectively.