Question

Plz help..............refresh the page before u answer

Answer 1

If you factor the denominator of the left multiplicand...

[(a-4)(a+3)]/[a(a-4)] you can see that the (a-4)s cancel out leaving:

(a+3)/a

now you have

(a+3)/a * 2a^3/((a+3)(a-1)) so the (a+3)s cancel out leaving:

1/a * 2a^3/(a-1) which is:

2a^3/(a(a-1)) so now a^1 cancel leaving

2a^2/(a-1)