Question

Please help me solve f^-1(3) when f(x)= 2x-7/3

Answer 1

Given a function
`f(x)`, we can solve for
`f^(-1)(y)` for some
`y` by solving for
`x` in the equation
`f(x)=y`.

I'm not sure whether your function
`f(x)` is
`2x-(7)/(3)` or
`(2x-7)/(3)`, so I'll solve it separately for each.

In the first case, we have
`2x-(7)/(3)=3`, so adding
`(7)/(3)` to both sides,
`2x=(16)/(3)`. Dividing by two gives
`x=(8)/(3)`.

In the second, we have
`(2x-7)/(3)=3`, so multiplying by three gives
`2x-7=9`, and adding seven gives
`2x=16`. Dividing by two gives
`x=8`.