Question

The average adult exhales about 1.0 kg of carbon dioxide each day. How much oxygen is needed in metabolizing glucose (C6H12O6, 180 g/mol) to make that much carbon dioxide? Somebody answer this for me i searched for it and it brought me to this site but when i try to get the answer it just brings me to this page. But no answer to be found

Answer 1

The overall equation of aerobic breakdown of glucose is:
C₆H₁₂O₆ + 3O₂ → 6CO₂ + 6H₂O

m(CO₂)=1.0 kg
M(CO₂)=44.01 kg/kmol
M(O₂)=32.00 kg/kmol

m(O₂)=M(O₂)m(CO₂)/(2M(CO₂))
m(O₂)=32.00*1.0/(2*44.01)=0.3636 kg=363.6 g

363.6 g oxygen is needed

Answer 2

0.72727 kg of oxygen is needed in metabolizing glucose to make 1.0 kg of carbon dioxide.

Step-by-step explanation:

`C_6H_(12)O_6+6O_2\rightarrow 6CO_2+6H_2O`

Mass of carbon dioxide exhaled by an adult = 1.0 kg = 1000 g

Moles of carbon dioxide =
`(1000 kg)/(44 g/mol)=22.7272 mol`

According to reaction,6 moles of carbon dioxide is produced when 1 mole of glucose.

Then 22.7272 moles of carbon dioxide will be produce by:

`(1)/(6)* 22.7272 mol=3.7878 mol` of glucose

According to reaction 1 mol of glucose reacts with 6 moles of oxygen :

Then 3.7878 moles of glucose will react with

`(6)/(1)* 3.7878mol=22.7272 mol` of oxygen

Mass of 22.7272 moles of oxygen gas:

`22.7272 mol* 32 g/mol=727.27 g=0.72727 kg`

0.72727 kg of oxygen is needed in metabolizing glucose to make 1.0 kg of carbon dioxide.