Question

Eli has 7 black pens and 5 blue pens in his desk drawer. he also has 3 yellow highlighters, 2 green highlighters, and 5 pink highlighters in his pencil case. If he chooses one pen and one highlighter without looking, what is the probability that he will get a black pen and he will not get a green highlighter?

Answer 1

7/22 or 31% chance of getting black pen
2/22 or 9% chance he will not get a green highlighter

Answer 2

The probability is 7/15.

Explanation:

Total number of pens = 7+5 = 12

Out of 12, 7 are black and 5 are blue pens.

Similarly, total number of highlighters = 3+2+5 = 10

Out of 10, 3 are yellow highlighters, 2 are green highlighters, and 5 are pink .

Now, Eli is choosing one pen and one highlighter without looking, so the probability that he will get a black pen and he will not get a green highlighter will be =
`(7)/(12)*(8)/(10)`

=
`(7)/(15)`

Hence, the probability is 7/15 or 46.66%.