Question

Is the solution below correct? explain. 9x+2=8x^2+6x

Answer 1

First, we have this...

`9x+2=8x^2+6`
Subtract
`8x^2+6x` from both sides.

`9x+2-\left(8x^2+6x\right)=8x^2+6x-\left(8x^2+6x\right)`
Simplify.

`-8x^2+3x+2=0`
Formula:

`x_(1,\:2)=(-3\pm √(3^2-4\left(-8\right)2))/(2\left(-8\right))`
Plug in the numbers..

`(-3+√(3^2-4\left(-8\right)\cdot \:2))/(2\left(-8\right))`
Simplify...

`=-(√(73)-3)/(16)`
We are going to do the same, just with a different operation...

`(-3-√(3^2-4\left(-8\right)\cdot \:2))/(2\left(-8\right))`
Simplify.

`=(√(73)+3)/(16)`

So, the solutions are...

`x=-(-3+√(73))/(16),\:x=(√(73)+3)/(16)`

Have a nice day! :)

Answer 2

Sample Response/Explanation: No. The correct values of a, b, and c were substituted in, but the formula was simplified wrong. The 64 should be added so the radicand is 73. There should be 2 real roots.