Question

A 63 kg object needs to be lifted 7 meters in a matter of 5 secound. Approximately how much horsepower is required to achieve in the task

Answer 1

work = mgh

power = mgh/t = 63•9.8•7/5 = 864 watts

1 HP = 746 watts

so that is 834/746 = 1.2 HP

Answer 2

A=ΔEp=mgh=63kg*9.81m/s2*7m=4326.21J
P=A/t=4326.21J/5s=865.24W=1.16hp
1kW=1.34hp