Question

Write the equation of a line in slope intercept form that passes through (-15,20) and is parallel to x-5 y=5

y=1/5x-19
y=-1/5x+17
y=1/5x+23
y=x+35

Answer 1

y = 1/5x + 23

Explanation:

parallel lines have the same slope.

x - 5y = 5

rearranging:

5y = x - 5

y = 1/5x - 1

Hence, the slope is 1/5. (Our new line shall have this same slope)

Equation of a line through point (x1, y1) and having slope m is:

y - y1 = m(x - x1)

substituting values:

y -20 = 1/5(x +15)

simplify

y -20 = 1/5x + 3

y = 1/5x + 23