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√(3x) √(6x) √(14x) can anybody help me out? I think I know what I am doing but, can anyone explain it in detail?
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Sep 2, 2018
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can anybody help me out? I think I know what I am doing but, can anyone explain it in detail?
Mathematics
college
Chalup
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sqrt{a} × sqrt{b} = sqrt{ab}
and when you have a mix of numbers andw variable, i.e '6' and 'x', then just multiply numbers and multiply x's and sqrt the product of these both:
sqrt{3x} × sqrt{6x} × sqrt{14x}
= sqrt{3×6×14×x×x×x}
= sqrt{252x^3}
[this can be simplified to: 6x(sqrt{7x})]
Sheler
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Sep 4, 2018
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RULE:
√a.√b = √(a.b)
√a.√b.√c = √(a.b.c)
√3.x .√6.x . √14.x = √(3x)(6x)(14.x) = √252.x³ = √2².3².7.x².x
= 2.3.x.√7x; = 6x√7x
Bob White
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Sep 7, 2018
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Bob White
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