Question

A basketball team plays 3 games in a holiday tournament. According to the tree diagram, how many outcomes are possible?

a. 5
b. 6
c. 7
d. 8

Answer 1

Option d. 8 is the correct option.

Explanation:

A basketball team plays 3 games in a holiday tournament.

Let the chance of winning of the team be represented as W and losing by L

As per tree diagram attached we can see

In the first game

Number possibilities will be 2 either win or lose

After second games

Number of possibilities will be 4 [(L L), (L W), (W L), (W W)]

After third game

Number of possibilities will be 8 [ (L L), (L W), (W L), (W W), (L L), (L W), (W L), (W W)]

So total outcomes which are possible are 8.

Option d. 8 is the correct option.

Answer 2

Hence, the possible number of outcomes are:

Option: d ( d. 8)

Explanation:

It is given that:

A basketball team plays 3 games in a holiday tournament.

( We know that:

Tree diagrams display all the possible outcomes of an event. Each branch in a tree diagram represents a possible outcome )

The possible number of outcomes that are possible are:

8.

Let the team be denoted by 'A'

so, the outcome of the game may be winning(W) or losing(L) the game.