Question

A boat leaves a dock at 2:00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15 km/h and reaches the same dock at 3:00 pm how many minutes after 2:00 pm were the two boats closest together?

Answer 1

The two boats were closest together at 2:00 pm.

Step-by-step explanation:

To determine how many minutes after 2:00 pm the two boats were closest together, we need to find the point of intersection between their paths. Let's first find the coordinates of each boat at different times.

The southbound boat travels at a constant speed of 20 km/h. So at 2:00 pm, it will be at the dock (0, 0) and at 3:00 pm, it will be 20 km south at (0, -20).

The eastbound boat travels at a constant speed of 15 km/h. So at 2:00 pm, it will be at the dock (0, 0) and at 3:00 pm, it will be 15 km east at (15, 0).

To find the point of intersection, we need to solve the simultaneous equations x = 0 and y = 0. This means the boats will intersect at the origin (0, 0).

Since the boats are at their closest when they intersect, the closest time to 2:00 pm when they are closest together is 2:00 pm itself.

Answer 2

2=_20+_ make a graph or table then u find out when