Question

`(3)/(2n) + (1)/(n^2) = (n-2)/(2n^2)`

Answer 1

make denomenators the same
common denom is 2n²

multiply 3/2n by n/n
mulitply 1/n² by 2/2

we get

`(3n)/(2n^2)+(2)/(2n^2)=(n-2)/(2n^2)`
combine fractions

`(3n+2)/(2n^2)=(n-2)/(2n^2)`
multiply both sides by 2n²
2n+2=n-2
minus n both sides
n+2=-2
minus 2 both sides
n=-4