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What is the percent of N in AgNO3?

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AgNO3 Mol mass = 108 + 14 + 48 = 170g/mol.
.N = 14 / 170 = 0.0824 x 100% = 8.24% 'N'.
User Onxx
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Answer:

8.24%

Step-by-step explanation:

User Kabucey
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