Question

How many moles of electrons are required to reduce one mole of oxygen gas (O2) to two moles of oxygen ions (O2-)?

2 e-
4 e-
6 e-
8 e-

Answer 1

O₂ + 4e⁻ ------> 2O²⁻

:)

Answer 2

The correct answer is 4 electrons.

Step-by-step explanation:

Reduction reaction is defined as chemical reaction in which element gains electrons and it get reduced. Also oxidation state of that element also deceases.

`O_2+e^-\rightarrow 2O^(2-)`

Charge on both sides should be balanced so for that write 4 as a coefficient of en electron in an above reaction.By this the charge on booth sides becomes (4-).

`O_2+4e^-\rightarrow 2O^(2-)`

1 mole of oxygen gas gets reduced by 4 electrons into 2 moles of oxygen ions.