Question

How many moles of aluminum oxide AI203 can be produced from 12.8 moles of oxygen gas O2 reacting with excess aluminum Al

Answer 1

4Al + 3O₂ ----> 2Al₂O₃
3 moles 2 moles

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3 moles of O₂ ---------- 2 moles of Al₂O₃
12,8 moles of O₂ -------- X
X = (12,8×2)/3 = 25,6/3
X = 8,533 moles of Al₂O₃

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