Question

10 Points.) A stone weighing 0.7 kilograms rolls down the inclined plane from position B to position A. Position A is located at sea level. The Inclined Plane is 0.25 Meters high.  The difference in the gravitational potential energy of the ball between positions A and B is about___ joules. (Use PE = m × g × h, where g = 9.8 N/kg.)

Answer 1

The potential energy of the moss is 147 Joules

Answer 2

Answer : 1.715 J

Explanation :

It is given that :

Mass of stone, m = 0.7 kg

The ball rolls down the inclined position from B to A and position A is located at sea level.

Height of inclined plane, h = 0.25 m

Gravitational potential energy at point A = 0 ( since, at point A PE = 0 )

Gravitational potential energy at point B = m g h

where,

m is the mass of ball

g is acceleration due to gravity

h is the height

So, at B potential energy will be :

`PE_B=0.7\ kg* 9.8\ m/s^2* 0.25\ m`

`PE_B =1.715\ J`

So, the difference in the gravitational potential energy of the ball between positions A and B is :

`PE_B-PE_A=1.715\ J`

Hence, this is the required solution.