Question

What is the distance between points (-2, 8) and (6, -2)? Round to the nearest tenth of a unit.

Answer 1

Distance formula:

`√((x_2-x_1)^2+(y_2-y_1)^2)`

We are given 2 coordinates:
(-2,8) and (6,-2)
x1,y1 x2,y2

Plug the numbers into the formula:


`√((6-(-2))^2+(-2-8)^2)`

Simplify:

`√((8)^2+(-10)^2)`

8^2=64
-10^2=100

`√(100+64)`

`√(164)=12.806248474865697`

The question asks to round to the nearest tenth so final answer:
12.8

Answer 2

distance formula:
`\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y{1})^(2)}`


`\sqrt{(-2-6)^(2)+(8-(-2))} \\ \sqrt{(-8)^(2)+(10)^(2)} \\ √(64+100) \\ √(164) = 2√(41) = 12.8062 = 12.8`