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Which are the solutions of x2 = –13x – 4? 0, 13 0, –13

User Gvl
by
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1 Answer

5 votes

Answer:

Roots are 0 , -13.

Explanation:

Given : x² = –13x – 4.

To find : Which are the solutions.

Solution : We have given that x² +13x + 4 = 0.

By discriminate formula

For quadratic equation a² +bx + c = 0.


x_(1) =
\frac{-b ±\sqrt{b^(2) -4 a * c } }{2}.

Plugging the values


x_(1) =
\frac{-13 ±\sqrt{13^(2) -4 *1  * 4}}{2}.


x_(1) =
\frac{-13 +\sqrt{13^(2) -4 *1  * 4}}{2}.


x_(1) =
(-13 +√(169 - 16))/(2).


x_(1) =
(-13 +√(153))/(2).


x_(1) =
(-0.6306)/(2).


x_(1) = -0.3153.

Approximate 0


x_(2) =
\frac{-13 -\sqrt{13^(2) -4 *1  * 4}}{2}.


x_(2) =
(-13 -√(169 -16))/(2).


x_(2) =
(-13 -√(153))/(2).


x_(2) =
(-25.36)/(2).


x_(2) = -12.68

Approximate - 13

Therefore, Roots are 0 , -13.

User Azad Prajapat
by
7.5k points

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