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Carlos does a chin-up in gym class and raises himself 0.8 m. If Carlos has a mass of 62 kg how much work does he accomplish?​

User Mick Knutson
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2 Answers

23 votes
23 votes

Final answer:

Carlos does 486.576 Joules of work by lifting his 62 kg body 0.8 m against gravity during a chin-up. To find this, his mass is multiplied by the acceleration due to gravity to get the force, then multiplied by the displacement to get work.

Step-by-step explanation:

The question involves calculating the work done by Carlos when he performs a chin-up. Work is a physical concept in physics, defined as the product of force along the direction of displacement and the displacement itself. Since Carlos is lifting his own body vertically against the gravitational force, the force equates to his weight (mass times the acceleration due to gravity). The work accomplished by Carlos can be found using the formula Work = Force x Displacement.

To calculate Carlos's weight, you multiply his mass by the acceleration due to gravity (9.81 m/s2):

Weight = Mass x Gravity

Weight = 62 kg x 9.81 m/s2

Weight = 608.22 N (newtons)

Now, we can use the weight as the force to calculate work:

Work = Force x Displacement

Work = 608.22 N x 0.8 m

Work = 486.576 Joules

Therefore, Carlos accomplishes 486.576 Joules of work when he raises himself 0.8 m during a chin-up.

User Teawithfruit
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2.8k points
24 votes
24 votes

Answer:486.1 J

Step-by-step explanation:

User Jakub Kubrynski
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3.1k points