Question

What is the mass for 3.01*10 23 molecules h2o

Answer 1

The answer is 8.99 g of water

Step-by-step explanation:

First we calculate the molecular mass of water, as follows. using the periodic table we have the masses of hydrogen and oxygen:

MW of H2 2 x 1 g/mol=2g/mol

MW of O: 16 g/mol

MW of H2O=2+16=18 g/mol

using Avogadro's number and making a simple direct rule of three we have:

6.023x
`10^(23)`mol----------------------18 g

3.01x
`10^(23)` mol------------------------ Xg

Clearing the X, we have:

`X = (18 g x 3.01x10^(23)mol )/(6.023x10x^(23) mol)=8.99 g of water`

Answer 2

M H₂O: 1g×2 + 16g = 18g


6,02×10²³ --------- 18g
3,01×10²³ --------- Xg
X = (18×3,01×10²³)/6,02×10²³
X = 9g

:)