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In the figure, the radius of the partial circle with center A is 4 feet.

The perimeter of the figure is ___ feet, and the area of the figure is ___ square feet.

Assume π = 3.14, and round your answers to the nearest hundredth.

Options for blank 1 are: 18.84, 24.50, 26.84, 75.36
Options for blank 2 are: 11.42, 22.84, 45.68, 53.68

In the figure, the radius of the partial circle with center A is 4 feet. The perimeter-example-1
User Chuan Ma
by
8.1k points

2 Answers

4 votes

Answer:

first blank : 24.50 feet

second blank : 45.68 square feet

Explanation:

edmentum

User Sergei Rodionov
by
7.8k points
2 votes

Step 1

Find the perimeter of the figure

we know that

the perimeter of a circle is equal to the circumference


C=2\pi r

where

C is the circumference of the circle

r is the radius of the circle

we have


r=4\ ft

substitute


C=2(3.14)4=25.12\ ft

In the figure

the triangle ABC is a right triangle

Applying the Pythagoras Theorem find the length side CB


CB^(2)=AB^(2) +AC^(2)

we have


AC=AB=4\ ft

substitute the values


CB^(2)=4^(2) +4^(2)


CB^(2)=32


CB=√(32)\ ft


CB=5.66\ ft

The perimeter of the figure is equal to
(3)/(4) of the circumference plus the length side CB

so


P=(3)/(4)25.12+5.66=24.50\ ft

therefore

the answer Part a) is

the perimeter of the figure is
24.50\ ft

Step 2

Find the area of the figure

we know that

the area of a circle is equal to


A=\pi r^(2)

where

r is the radius of the circle

we have


r=4\ ft

substitute


A=3.14(4^(2))=50.24\ ft^(2)

the area of the triangle ABC is equal to


A=(1)/(2) bh

in this problem


b=BC=√(32)\ ft


h=BC/2=√(32)/2\ ft

substitute the values


A=(1)/(2)(√(32))(√(32)/2)=8\ ft^(2)

the area of the figure is equal to
(3)/(4) of the area of the circle plus the area of the triangle ABC


A=(3)/(4)*50.24+8=45.68\ ft^(2)

therefore

the answer Part b) is

the area of the figure is
45.68\ ft^(2)

User Manuel M
by
7.8k points