Question

The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is the resistance of the circuit. What is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts

Answer 1

Since we are given the equation P = I2R and the measures of variables in the equation, our first step is to identify each variable.

Since there is a resistance of 30 ohms, R = 30Ω.
Since there is power of 2 watts, P = 2 W.

The variable we are trying to solve for is I, current.

Now we can plug the given information into the equation and solve for I:

`P=I2R \\ 2=I(2)(30) \\ 2=I(60) \\ I= (2)/(60) \\ I= (1)/(30) =0.033`

Current (I) = 1/30 A, or 0.033 A.

Hope this helps!

Answer 2

0.2581 Ampere is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts.

Step-by-step explanation:

The power (P)in an electrical circuit is given by the equation:

`P=I^2R`

I = Current in the circuit

R = Resistance offered by the circuit

p = 2 watts, R = 30 Ω

I = ?

`2 Watts=I^2* 30\Omega`

`I=\sqrt{(2 Watts)/(30 \Omega)}`

I = 0.2581 Ampere