Question

F a shell can hold a maximum of 32 electrons, what is the value of n? 2 3 4 5

Answer 1

The shell which holds 32 electrons is fourth shell.

Step-by-step explanation:

Principle Quantum Numbers: This quantum number describes the size of the orbital. It is represented by n.

Number of elections in nth shell is given by formula :
`2n^2`

Number of electrons in ,n=1 :
`2(1)^2=2`

Number of electrons in ,n=2 :
`2(2)^2=8`

Number of electrons in ,n=3 :
`2(3)^2=18`

Number of electrons in ,n=4 :
`2(4)^2=32`

Number of electrons in ,n=4 :
`2(5)^2=50`

The shell which holds 32 electrons is fourth shell.

Answer 2

Answer: 4

Explanation:

Principle Quantum Numbers: This quantum number describes the size of the orbital. It is represented by n.

Azimuthal Quantum Number: This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number: This quantum number describes the orientation of the orbitals. It is represented as
`m_l`. The value of this quantum number ranges from
`(-l\text{ to }+l)`. When l = 2, the value of
`m_l` will be -2, -1, 0, +1, +2.

Given : a f subshell, thus l = 3 , Thus the subshells present would be 3, 2, 1, 0 and thus n will have a value of 4.

Also electrons give are 32.

The formula for number of electrons is
`2n^2`.

`2n^2=32`

`n=4`

Thus principal quantum no will be n= 4.