Question

How much heat is required to increase the temperature of 10.0 grams of water 6.0oC? (The specific heat of water is 4.18 J/g x oC)

Answer 1

Answer: 250.8 Joules

Step-by-step explanation:

Using the equation below:

`Q= m* c* \Delta T`

Q= heat gained

m= mass of the substance = 10.0 g

c = heat capacity of water= 4.18 J/g ° C

`\Delta T={\text{Change in temperature}}=6^oC`

`Q=10g* 4.18J/g^oC*6^oC`

Q= 250.8 Joules

Thus heat gained by 10 g of water is = 250.8 Joules

Answer 2

Heat required in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 10(4.18)(6)
Heat = 250.8 J --------------> OPTION A